Subsets and Subgroups
Let (G,\star) be a group.
(H,\star) is a subgroup of (G,\star) if
(1) (H,\star) is a group
(2) H is a subset of G.
This is notated H \leq G.
Let G be a group, and H be a subgroup of G. The subgroup H = G itself is the improper subgroup. All other subgroups are proper.
Let G be a group. The subgroup \{e_G\} is the trivial subgroup. All other subgroups are nontrivial.
A subset H of a closed group G is a subgroup of G if and only if
(1) H is closed under the binary operation of G
(2) The identity e_G is in H
(3) For all a \in H, a^{-1} \in H.
Let H be a finite nonempty subset
Cyclic Subgroups
Let G be a group and let a \in G. Then
H = \{a^n \mid n \in \mathbb{Z}\}
is a subgroup of G and is the smallest subgroup of G that contains a. Furthermore, every subgroup containing a contains H.
Let G be a group and let a \in G. Then the subgroup above is known as the cyclic subgroup of G generated by a.
A group G is cyclic if and only if there exist some a such that \langle a\rangle = G.
Every cyclic group is abelian
Let G be a cyclic group and let a generate G.
If g_1 and g_2 are any two elements of G, there exists integers r and s such that g_1 = a^r and g_2 = a^s. Then
g_1g_2 = a^ra^s = a^{r+s} = a^{s+r} = a^sa^r = g_2g_1.
So G is abelian.
Let m be a positive integer and n be any integer. There exists integers q,r sich that
n = mq + r \quad\text{and}\quad 0 \leq r < m.
A subset of a cyclic group is cyclic.
Let G be a cyclic group generated by a and let H be a subgroup of G.